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  1. What will be the output of the program ?

      #include
  int main()
  {  
      int a[5] = {5, 1, 15, 20, 25};     
      int i, j, m;  
      i = ++a[1];  
      j = a[1]++;    
      m = a[i++];     
      printf("%d, %d, %d", i, j, m);     
      return 0;
 }

    2. A.

    2, 1, 15
    B.

    1, 2, 5
    C.

    3, 2, 15
    D.

    2, 3, 20

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    Answer : Option C

    Explanation :

    Step 1: int a[5] = {5, 1, 15, 20, 25}; The variable arr is declared as an integer array with a size of 5 and it is initialized to

    a[0] = 5, a[1] = 1, a[2] = 15, a[3] = 20, a[4] = 25 .

    Step 2: int i, j, m; The variable i,j,m are declared as an integer type.

    Step 3: i = ++a[1]; becomes i = ++1; Hence i = 2 and a[1] = 2

    Step 4: j = a[1]++; becomes j = 2++; Hence j = 2 and a[1] = 3.

    Step 5: m = a[i++]; becomes m = a[2]; Hence m = 15 and i is incremented by 1(i++ means 2++ so i=3)

    Step 6: printf("%d, %d, %d", i, j, m); It prints the value of the variables i, j, m

    Hence the output of the program is 3, 2, 15

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