Arrays - C Programming Questions and Answers

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What will be the output of the program ?

#include 

 int main() 
 {  
     void fun(int, int[]); 
     int arr[] = {1, 2, 3, 4};     
     int i; 
     fun(4, arr);  
     for(i=0; i4; i++)          
        printf("%d,", arr[i]);     
     return 0;
 } 
 void fun(int n, int arr[])
 {     
     int *p=0; 
     int i=0;   
     while(i++ 0;
 }

2, 3, 4, 5

1, 2, 3, 4

0, 1, 2, 3

3, 2, 1 0

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Answer : Option B

Explanation :

Step 1: void fun(int, int[]); This prototype tells the compiler that the function fun() accepts one integer value and one array as an arguments and does not return anything.

Step 2: int arr[] = {1, 2, 3, 4}; The variable a is declared as an integer array and it is initialized to

a[0] = 1, a[1] = 2, a[2] = 3, a[3] = 4

Step 3: int i; The variable i is declared as an integer type.

Step 4: fun(4, arr); This function does not affect the output of the program. Let's skip this function.

Step 5: for(i=0; i The for loop runs untill the variable i is less than '4' and it prints the each value of array a.