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What will be the output of the program ?

 #include
  int main()
  {    
    float arr[] = {12.4, 2.3, 4.5, 6.7};   
   printf("%d\n", sizeof(arr)/sizeof(arr[0]));      
   return 0;
 }

Answer : Option B

Explanation :

The sizeof function return the given variable. Example: float a=10; sizeof(a) is 4 bytes

Step 1: float arr[] = {12.4, 2.3, 4.5, 6.7}; The variable arr is declared as an floating point array and it is initialized with the values.

Step 2: printf("%d\n", sizeof(arr)/sizeof(arr[0]));

The variable arr has 4 elements. The size of the float variable is 4 bytes.

Hence 4 elements x 4 bytes = 16 bytes

sizeof(arr[0]) is 4 bytes

Hence 16/4 is 4 bytes

Hence the output of the program is '4'.

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