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What will be the output of the program if the array begins 1200 in memory?

  #include
 
   int main() 
   {   
       int arr[]={2, 3, 4, 1, 6};      
       printf("%u, %u, %u\n", arr, &arr[0], &arr); 
      return 0; 
   }

1200, 1202, 1204

1200, 1200, 1200

1200, 1204, 1208

1200, 1202, 1200

Answer : Option B

Explanation :

Step 1: int arr[]={2, 3, 4, 1, 6}; The variable arr is declared as an integer array and initialized.

Step 2: printf("%u, %u, %u\n", arr, &arr[0], &arr); Here,

The base address of the array is 1200.

=> arr, &arr is pointing to the base address of the array arr.

=> &arr[0] is pointing to the address of the first element array arr. (ie. base address)