Discussion :: Arrays
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What will be the output of following program code?
#include <stdio.h>
int main(void)
{
char p;
char buf[10] = {1, 2, 3, 4, 5, 6, 9, 8};
p = (buf + 1)[5];
printf("%d", p);
return 0;
}
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Answer : Option C
Explanation :
x[i] is equivalent to *(x + i),
so (buf + 1)[5] is *(buf + 1 + 5), i.e. buf[6].
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