Discussion :: C Preprocessor
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What will be the output of the program?
#include #define JOIN(s1, s2) printf("%s=%s %s=%s \n", #s1, s1, #s2, s2); int main() { char *str1="Fresher"; char *str2="GATE"; JOIN(str1, str2); return 0; }
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A.
str1=FresherGATE str2=GATE |
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B.
str1=FresherGATE str2=GATE |
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C.
str1=Fresherstr2=FresherGATE |
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D.
Error: in macro substitution |
Answer : Option B
Explanation :
No answer description available for this question.
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