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  1. What will be the output of the program?

     #include
 #define PRINT(int) printf("int=%d, ", int);

  int main()
  {     
     int x=2, y=3, z=4;        
     PRINT(x);  
     PRINT(y);  
     PRINT(z);  
     return 0; 
 }

    2. A.

    int=2, int=3, int=4
    B.

    int=2, int=2, int=2
    C.

    int=3, int=3, int=3
    D.

    int=4, int=4, int=4

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    Answer : Option A

    Explanation :

    The macro PRINT(int) print("%d,", int); prints the given variable value in an integer format.

    Step 1: int x=2, y=3, z=4; The variable x, y, z are declared as an integer type and initialized to 2, 3, 4 respectively.

    Step 2: PRINT(x); becomes printf("int=%d,",x). Hence it prints 'int=2'.

    Step 3: PRINT(y); becomes printf("int=%d,",y). Hence it prints 'int=3'.

    Step 4: PRINT(z); becomes printf("int=%d,",z). Hence it prints 'int=4'.

    Hence the output of the program is int=2, int=3, int=4.

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