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What will be the output of the program?

 #include
 #define FUN(arg) do\                    
                  {\                       
                    if(arg)\                         
        printf("FresherGATE...", "\n");\                
             }while(--i)  
 int main()
 {    
     int i=2;    
     FUN(i3);    
     return 0;
 }

FresherGATE...
FresherGATE...
FresherGATE

FresherGATE... FresherGATE...

Error: cannot use control instructions in macro

No output

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Answer : Option B

Explanation :

The macro FUN(arg) prints the statement "IndiaBIX..." untill the while condition is satisfied.

Step 1: int i=2; The variable i is declared as an integer type and initialized to 2.

Step 2: FUN(i becomes,

do {     if(2 3)     printf("IndiaBIX...", "\n"); }while(--2)

After the 2 while loops the value of i becomes '0'(zero). Hence the while loop breaks.