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  1. What will be the output of the program?

     #include 
 #define PRINT(i) printf("%d,",i) 

 int main()
 {   
    int x=2, y=3, z=4;  
    PRINT(x);     
    PRINT(y);   
    PRINT(z);    
    return 0;
 }

    2. A.

    2, 3, 4,
    B.

    2, 2, 2,
    C.

    3, 3, 3,
    D.

    4, 4, 4,

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    Answer : Option A

    Explanation :

    The macro PRINT(i) print("%d,", i); prints the given variable value in an integer format.

    Step 1: int x=2, y=3, z=4; The variable x, y, z are declared as an integer type and initialized to 2, 3, 4 respectively.

    Step 2: PRINT(x); becomes printf("%d,",x). Hence it prints '2'.

    Step 3: PRINT(y); becomes printf("%d,",y). Hence it prints '3'.

    Step 4: PRINT(z); becomes printf("%d,",z). Hence it prints '4'.

    Hence the output of the program is 2, 3, 4.

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