Menu
Home / C Programming / C Preprocessor :: Discussion

Discussion :: C Preprocessor

  1. What will be the output of the program?

    #include<stdio.h>
    #define int char 
    void main()
    {
          int i = 65;
          printf("sizeof(i)=%d", sizeof(i));
    }
    2. A.

     sizeof(i)=2
    B.

     sizeof(i)=1
    C.

     Compiler Error
    D.

     None of These

    View Answer

    Workspace

    View Answer

    Answer : Option B

    Explanation :

    Since the #define replaces the string int by the macro char.
    So, here i is a variable of type char and not int.

Write your comments here:

Be The First To Comment