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  1. What will be the output of the program?

     #include 
 int main()
 {   
     const int x=5;    
     const int *ptrx;   
     ptrx = &x;     
     *ptrx = 10;    
     printf("%d\n", x);     
     return 0;
 }

    2. A.

    5
    B.

    10
    C.

    Error
    D.

    Garbage value

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    Workspace

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    Answer : Option C

    Explanation :

    Step 1: const int x=5; The constant variable x is declared as an integer data type and initialized with value '5'.

    Step 2: const int *ptrx; The constant variable ptrx is declared as an integer pointer.

    Step 3: ptrx = &x; The address of the constant variable x is assigned to integer pointer variable ptrx.

    Step 4: *ptrx = 10; Here we are indirectly trying to change the value of the constant vaiable x. This will result in an error.

    To change the value of const variable x we have to use *(int *)&x = 10;

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