Discussion :: Const
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What will be the output of the program?
#include
Answer : Option B
Explanation :
Step 1: const c = -11; The constant variable 'c' is declared and initialized to value "-11".
Step 2: const int d = 34; The constant variable 'd' is declared as an integer and initialized to value '34'.
Step 3: printf("%d, %d\n", c, d); The value of the variable 'c' and 'd' are printed.
Hence the output of the program is -11, 34
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