Discussion :: Control Instructions
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What will be the output of the program?
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Answer : Option D
Explanation :
Step 1: int i = 0; here variable i is an integer type and initialized to '0'.
Step 2: for(; i variable i=0 is already assigned in previous step. The semi-colon at the end of this for loop tells, "there is no more statement is inside the loop".
Loop 1: here i=0, the condition in for(; 0i is incremented by '1'(one)
Loop 2: here i=1, the condition in for(; 1i is incremented by '1'(one)
Loop 3: here i=2, the condition in for(; 2i is incremented by '1'(one)
Loop 4: here i=3, the condition in for(; 3i is increemented by '1'(one)
Loop 5: here i=4, the condition in for(; 4i is incremented by '1'(one)
Loop 6: here i=5, the condition in for(; 5i is incremented by '1'(one)
Loop 7: here i=6, the condition in for(; 6i is not incremented.
Step 3: printf("%d", i); here the value of i is 6. Hence the output is '6'.
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