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  1. What will be the output of the program?

    #include 
int main()
 {     
     int i=-3, j=2, k=0, m;  
     m = ++i && ++j && ++k;   
     printf("%d, %d, %d, %d\n", i, j, k, m);  
     return 0;
 }

    2. A.

    -2, 3, 1, 1
    B.

    2, 3, 1, 2
    C.

    1, 2, 3, 1
    D.

    3, 3, 1, 2

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    Answer : Option A

    Explanation :

    Step 1: int i=-3, j=2, k=0, m; here variable i, j, k, m are declared as an integer type and variable i, j, k are initialized to -3, 2, 0 respectively.

    Step 2: m = ++i && ++j && ++k;
    becomes m = -2 && 3 && 1;
    becomes m = TRUE && TRUE; Hence this statement becomes TRUE. So it returns '1'(one). Hence m=1.

    Step 3: printf("%d, %d, %d, %d\n", i, j, k, m); In the previous step the value of i,j,k are increemented by '1'(one).

    Hence the output is "-2, 3, 1, 1".

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