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What will be the output of the program?

#include 
int main()
 {     
     int i=-3, j=2, k=0, m;   
     m = ++i && ++j || ++k;   
     printf("%d, %d, %d, %d\n", i, j, k, m);   
     return 0; 
}

1, 2, 0, 1

-3, 2, 0, 1

-2, 3, 0, 1

2, 3, 1, 1

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Answer : Option C

Explanation :

Step 1: int i=-3, j=2, k=0, m; here variable i, j, k, m are declared as an integer type and variable i, j, k are initialized to -3, 2, 0 respectively.

Step 2: m = ++i && ++j || ++k;
becomes m = (-2 && 3) || ++k;
becomes m = TRUE || ++k;.
(++k) is not executed because (-2 && 3) alone return TRUE.
Hence this statement becomes TRUE. So it returns '1'(one). Hence m=1.

Step 3: printf("%d, %d, %d, %d\n", i, j, k, m); In the previous step the value of i,j are increemented by '1'(one).