Discussion :: Expressions
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What will be the output of the program?
#includeint main() { int i=2; int j = i + (1, 2, 3, 4, 5); printf("%d\n", j); return 0; }
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Answer : Option B
Explanation :
Because, comma operator used in the expression i (1, 2, 3, 4, 5). The comma operator has left-right associativity. The left operand is always evaluated first, and the result of evaluation is discarded before the right operand is evaluated. In this expression 5 is the right most operand, hence after evaluating [removed]1, 2, 3, 4, 5) the result is 5, which on adding to i results into 7.
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