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Discussion :: Floating Point Issues

  1. What will be the output of the program?

     #include
 #include<math.h>
 int main() 
 {   
     printf("%f\n", sqrt(36.0));       
     return 0;
 }

    2. A.

    6.0
    B.

    6
    C.

    6.000000
    D.

    Error: Prototype sqrt() not found.

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    Answer : Option C

    Explanation :

    printf("%f\n", sqrt(36.0)); It prints the square root of 36 in the float format(i.e 6.000000).

    Declaration Syntax: double sqrt(double x) calculates and return the positive square root of the given number.

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