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  1. What will be the output of the program?

    #include 
 int main()
 {
     int fun(int);    
     int i = fun(10); 
     printf("%d\n", --i);  
     return 0; 
}
int fun(int i) 
{   
    return (i++); 
}

     

    2. A.

    9
    B.

    10
    C.

    11
    D.

    8

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    Answer : Option A

    Explanation :

    Step 1: int fun(int); Here we declare the prototype of the function fun().

    Step 2: int i = fun(10); The variable i is declared as an integer type and the result of the fun(10) will be stored in the variable i.

    Step 3: int fun(int i){ return (i++); } Inside the fun() we are returning a value return(i++). It returns 10. because i++ is the post-increement operator.

    Step 4: Then the control back to the main function and the value 10 is assigned to variable i.

    Step 5: printf("%d\n", --i); Here --i denoted pre-increement. Hence it prints the value 9.

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