Discussion :: Functions
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What will be the output of the program?
#includeint main() { int i=1; if(!i) printf("FRESHERGATE,"); else { i=0; printf("C-Program"); main(); } return 0; }
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A.
prints "FRESHERGATE, C-Program" infinitely |
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B.
prints "C-Program" infinetly |
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C.
prints "C-Program, FRESHERGATE" infinitely |
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D.
Error: main() should not inside else statement |
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Answer : Option B
Explanation :
Step 1: int i=1; The variable i is declared as an integer type and initialized to 1(one).
Step 2: if(!i) Here the !(NOT) operator reverts the i value 1 to 0. Hence the if(0) condition fails. So it goes to else part.
Step 3: else { i=0; In the else part variable i is assigned to value 0(zero).
Step 4: printf("C-Program"); It prints the "C-program".
Step 5: main(); Here we are calling the main() function.
After calling the function, the program repeats from step 1 to step 5 infinitely.
Hence it prints "C-Program" infinitely.
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