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  1. What will be the output of the program?

     #include
     int func1(int);  
     
     int main() 
     {    
         int k=35;    
         k = func1(k=func1(k=func1(k)));   
         printf("k=%d\n", k);    
         return 0;
     }
     int func1(int k)
     {     
         k++;  
         return k; 
     } 

     

  2. A.

    k=35

    B.

    k=36

    C.

    k=37

    D.

    k=38

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    Answer : Option D

    Explanation :

    Step 1: int k=35; The variable k is declared as an integer type and initialized to 35.

    Step 2: k = func1(k=func1(k=func1(k))); The func1(k) increement the value of k by 1 and return it. Here the func1(k) is called 3 times. Hence it increements value of k = 35 to 38. The result is stored in the variable k = 38.

    Step 3: printf("k=%d\n", k); It prints the value of variable k "38".


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