Menu
Home / C Programming / Functions :: Discussion

Discussion :: Functions

  1. Point out the error in the program

    #include

 int main()
 {     
    int a=10;  
    void f();     
    a = f();    
    printf("%d\n", a);   
    return 0;
 } 
 void f() 
 {    
    printf("Hi"); 
 }

     

    2. A.

    Error: Not allowed assignment
    B.

    Error: Doesn't print anything
    C.

    No error
    D.

    None of above

    View Answer

    Workspace

    View Answer

    Answer : Option A

    Explanation :

    The function void f() is not visible to the compiler while going through main() function. So we have to declare this prototype void f(); before to main() function. This kind of error will not occur in modern compilers.

Write your comments here:

Be The First To Comment