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  1. What will be the output of the program?

     #include
 #include 

 int main() 
 {   
      char dest[] = {97, 97, 0};      
      char src[] = "aaa";  
      int i;  
      if((i = memcmp(dest, src, 2))==0)      
       printf("Got it");     
   else         
        printf("Missed");     
    return 0;
 }

    2. A.

    Missed
    B.

    Got it
    C.

    Error in memcmp statement
    D.

    None of above

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    Answer : Option B

    Explanation :

    memcmp compares the first 2 bytes of the blocks dest and src as unsigned chars. So, the ASCII value of 97 is 'a'.

    if((i = memcmp(dest, src, 2))==0) When comparing the array dest and src as unsigned chars, the first 2 bytes are same in both variables.so memcmp returns '0'.
    Then, the if(0=0) condition is satisfied. Hence the output is "Got it".

     

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