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  1. Point out the error in the following program.

     #include
 #include 

  int main()
  {    
      char str1[] = "Learn through  FresherGATE0.com",  str2[120];       
      char *p;   
      p = (char*) memccpy(str2, str1, 'i', strlen(str1));    
     *p = '\0';    
      printf("%s", str2);  
      return 0; 
 }

    2. A.

    Error: in memccpy statement
    B.

    Error: invalid pointer conversion
    C.

    Error: invalid variable declaration
    D.

    No error and prints "Learn through Indi"

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    Workspace

    View Answer

    Answer : Option D

    Explanation :

    Declaration:
    void *memccpy(void *dest, const void *src, int c, size_t n); : Copies a block of n bytes from src to dest

    With memccpy(), the copying stops as soon as either of the following occurs:
    => the character 'i' is first copied into str2
    => n bytes have been copied into str2

     

     

     

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