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Discussion :: Memory Allocation

  1. What will be the output of the program?

    #include 
#include 
 
 int main()
 {    
      char *s;  
      char *fun();    
      s = fun();     
      printf("%s\n", s);    
      return 0;
 } 
 char *fun()
 {    
     char buffer[30];   
     strcpy(buffer, "RAM");     
     return (buffer); 
 }

    2. A.

    0xffff
    B.

    Garbage value
    C.

    0xffee
    D.

    Error

    View Answer

    Workspace

    View Answer

    Answer : Option B

    Explanation :

    The output is unpredictable since buffer is an auto array and will die when the control go back to main. Thus s will be pointing to an array , which not exists.

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