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Discussion :: Operators and Expressions

  1. What will be the output of this program on an implementation where int occupies 2 bytes?

    #include <stdio.h>
    void main()
    {
          int i = 3;
          int j;
          j = sizeof(++i + ++i);
          printf("i=%d j=%d", i, j);
    }
    2. A.

     i=4 j=2
    B.

     i=3 j=2
    C.

     i=5 j=2
    D.

     the behavior is undefined

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    Answer : Option B

    Explanation :

    Evaluating ++i + ++i would produce undefined behavior, but the operand of sizeof is not evaluated, so i remains 3 throughout the program. The type of the expression (int) is reduced at compile time, and the size of this type (2) is assigned to j.

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