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  1. What will be the output of the program ?

     #include

  int main()
  {     
      char p[] = "%d\n";   
      p[1] = 'c';    
      printf(p, 65); 
      return 0; 
}

    2. A.

    A
    B.

    a
    C.

    c
    D.

    65

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    Answer : Option A

    Explanation :

    Step 1: char p[] = "%d\n"; The variable p is declared as an array of characters and initialized with string "%d".

    Step 2: p[1] = 'c'; Here, we overwrite the second element of array p by 'c'. So array p becomes "%c".

    Step 3: printf(p, 65); becomes printf("%c", 65);

    Therefore it prints the ASCII value of 65. The output is 'A'.

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