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  1. What will be the output of the program ?

    #include 
 int main() 
 {   
    char str[7] = "FresherGATE";     
    printf("%s\n", str);   
    return 0; 
 }

    2. A.

    Error
    B.

    FresherGATE
    C.

    Cannot predict
    D.

    None of above

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    Workspace

    View Answer

    Answer : Option C

    Explanation :

    Here str[] has declared as 7 character array and into a 8 character is stored. This will result in overwriting of the byte beyond 7 byte reserved for '\0'.

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