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  1. What will be the output of the program ?

    #include 
 int main() 
 {    
    char *names[] = { "Suresh", "Siva", "Sona", "Baiju", "Ritu"};    
    int i;    
    char *t;  
    t = names[3];    
    names[3] = names[4];   
    names[4] = t; 
    for(i=0; i4; i++)         
        printf("%s,", names[i]);   
    return 0; 
}

    2. A.

    Suresh, Siva, Sona, Baiju, Ritu
    B.

    Suresh, Siva, Sona, Ritu, Baiju
    C.

    Suresh, Siva, Baiju, Sona, Ritu
    D.

    Suresh, Siva, Ritu, Sona, Baiju

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    Answer : Option B

    Explanation :

    Step 1: char *names[] = { "Suresh", "Siva", "Sona", "Baiju", "Ritu"}; The variable names is declared as an pointer to a array of strings.

    Step 2: int i; The variable i is declared as an integer type.

    Step 3: char *t; The variable t is declared as pointer to a string.

    Step 4: t = names[3]; names[3] = names[4]; names[4] = t; These statements the swaps the 4 and 5 element of the array names.

    Step 5: for(i=0; i These statement prints the all the value of the array names.

    Hence the output of the program is "Suresh, Siva, Sona, Ritu, Baiju".

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