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What will be the output of the program in 16-bit platform (Turbo C under DOS) ?

#include 

 int main() 
 {  
   printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0));   
   return 0;
 }

8, 1, 4

4, 2, 8

4, 2, 4

10, 3, 4

Answer : Option B

Explanation :

Step 1:

printf("%d, %d, %d", sizeof(3.0f), sizeof('3'), sizeof(3.0));

The sizeof function returns the size of the given expression.

sizeof(3.0f) is a floating point constant. The size of float is 4 bytes

sizeof('3') It converts '3' in to ASCII value.. The size of int is 2 bytes

sizeof(3.0) is a double constant. The size of double is 8 bytes

Hence the output of the program is 4,2,8

Note: The above program may produce different output in other platform due to the platform dependency of C compiler.