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  1. If char=1, int=4, and float=4 bytes size, What will be the output of the program ?

     #include
 
  int main()
  {    
       char ch = 'A';   
       printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14f));     
       return 0; 
  }

    2. A.

    1, 2, 4
    B.

    1, 4, 4
    C.

    2, 2, 4
    D.

    2, 4, 8

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    Answer : Option B

    Explanation :

    Step 1: char ch = 'A'; The variable ch is declared as an character type and initialized with value 'A'.

    Step 2:

    printf("%d, %d, %d", sizeof(ch), sizeof('A'), sizeof(3.14));

    The sizeof function returns the size of the given expression.

    sizeof(ch) becomes sizeof(char). The size of char is 1 byte.

    sizeof('A') becomes sizeof(65). The size of int is 4 bytes (as mentioned in the question).

    sizeof(3.14f). The size of float is 4 bytes.

    Hence the output of the program is 1, 4, 4

     

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