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  1. What will be the output of the program ?

    #include  

 int main()
 {    
     char t;  
     char *p1 = "Fresher", *p2;    
     p2=p1;     
     p1 = "GATE";     
     printf("%s %s\n", p1, p2);   
     return 0;
 }

    2. A.

    Fresher GATE
    B.

    GATE Fresher
    C.

     Fresher Fresher
    D.

    GATE GATE

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    Answer : Option B

    Explanation :

    Step 1: char *p1 = "Fresher", *p2; The variable p1 and p2 is declared as an pointer to a character value and p1 is assigned with a value "Fresher".

    Step 2: p2=p1; The value of p1 is assigned to variable p2. So p2 contains "Fresher".

    Step 3: p1 = "GATE"; The p1 is assigned with a string "GATE"

    Step 4: printf("%s %s\n", p1, p2); It prints the value of p1 and p2.

    Hence the output of the program is "GATE Fresher".

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