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  1. What will be the output of the following program in 16 bit platform assuming that 1022 is memory address of the string "Hello1" (in Turbo C under DOS) ?

     #include 

 int main()
 {   
    printf("%u %s\n", &"Hello1", &"Hello2");      
    return 0;
 }

    2. A.

    1022 Hello2
    B.

    Hello1 1022
    C.

    Hello1 Hello2
    D.

    1022 1022
    E.

    Error

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    Workspace

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    Answer : Option A

    Explanation :

    In printf("%u %s\n", &"Hello", &"Hello");.

    The %u format specifier tells the compiler to print the memory address of the "Hello1".

    The %s format specifier tells the compiler to print the string "Hello2".

    Hence the output of the program is "1022 Hello2".

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