Discussion :: Variable Number of Arguments
-
What will be the output of the program?
#include
void display(int num, ...); int main() { display(4, 'A', 'B', 'C', 'D'); return 0; } void display(int num, ...) { char c, c1; int j; va_list ptr, ptr1; vastart(ptr, num); va_start(ptr1, num); for(j=1; jint); printf("%c", c); c1 = va_arg(ptr1, int); printf("%d\n", c1); } }
Answer : Option C
Explanation :
No answer description available for this question.
Be The First To Comment