C Programming :: Bitwise Operators
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Assunming, integer is 2 byte, What will be the output of the program?
#include
int main() { printf("%x\n", -1>>1); return 0; } -
If an unsigned int is 2 bytes wide then, What will be the output of the program ?
#include
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Assuming a integer 2-bytes, What will be the output of the program?
#include
int main() { printf("%x\n", -13); return 0; } -
If an unsigned int is 2 bytes wide then, What will be the output of the program ?
#include
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What will be the output of the program?
#include
int main() { printf("%d >> %d %d >> %d\n", 4 >> 1, 8 >> 1); return 0; } -
What will be the output of the program?
#include
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What will be the output of the program?
#define P printf("%d\n", -1^~0); #define M(P) int main()\ {\ P\ return 0;\ } M(P)
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What will be the output of the program ?
#include
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What will be the output of the program?
#include
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What will be the output of the program ?
#include
int main() { int i=4, j=8; printf("%d, %d, %d\n", i|j&j|i, i|j&&j|i, i^j); return 0; }