C Programming :: Bitwise Operators
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Assunming, integer is 2 byte, What will be the output of the program?
#includeint main() { printf("%x\n", -1>>1); return 0; } -
If an unsigned int is 2 bytes wide then, What will be the output of the program ?
#include int main() { unsigned int m = 32; printf("%x\n", ~m); return 0; } -
Assuming a integer 2-bytes, What will be the output of the program?
#includeint main() { printf("%x\n", -13); return 0; } -
If an unsigned int is 2 bytes wide then, What will be the output of the program ?
#include int main() { unsigned int a=0xffff; ~a; printf("%x\n", a); return 0; } -
What will be the output of the program?
#includeint main() { printf("%d >> %d %d >> %d\n", 4 >> 1, 8 >> 1); return 0; } -
What will be the output of the program?
#include int main() { char c=48; int i, mask=01; for(i=1; i5; i++) { printf("%c", c|mask); maska= mask1; } return 0; } -
What will be the output of the program?
#define P printf("%d\n", -1^~0); #define M(P) int main()\ {\ P\ return 0;\ } M(P) -
What will be the output of the program ?
#include int main() { int i=32, j=0x20, k, l, m; k=i|j; l=i&j; m=k^l; printf("%d, %d, %d, %d, %d\n", i, j, k, l, m); return 0; } -
What will be the output of the program?
#include int main() { printf("%d %d\n", 321, 320); printf("%d %d\n", 321, 320); printf("%d %d\n", 32>>1, 32>>0); printf("%d %d\n", 32>>-1, 32>>-0); return 0; } -
What will be the output of the program ?
#includeint main() { int i=4, j=8; printf("%d, %d, %d\n", i|j&j|i, i|j&&j|i, i^j); return 0; }

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